2 Х. 3. 2. Х (0,6) = √(1 3 ) 2 (log. X) + 2log. x-3=o 3. 2

Question

2
Х. 3. 2. Х
(0,6) = √(1 3 )
2
(log. X) + 2log. x-3=o
3. 2

Answer 1

)

- X^2 - 2X + 8 = 0

D = 4-4*(-1)*8 = 4 + 32 = 36  V D = 6

X1 = 2 + 6 \ - 2= - 4

X2 = 2 - 6 \ - 2 = 2

2)

X^3 - 7X - 6 = 0

F' = 3X^2 - 7

3X^2 = 7

X^2 = 7\3

X = V 7\3