Помогите пожалуйста! решить Упростите выражение:

Решите задачу:

$1)( \frac{(x + 1 {)}^{2} - (x - 1 {)}^{2} }{ {x}^{2} - 1} ) \div ( \frac{(x + 1 {)}^{2} + (x - 1 {)}^{2} }{ {x}^{2} - 1 } ) = \frac{(x + 1 {)}^{2} - (x - 1 {)}^{2} }{ {x}^{2} - 1} \times \frac{ {x}^{2} - 1 }{(x + 1 {)}^{2} + ( {x - 1)}^{2} } = \frac{(x + 1 {)}^{2} - (x - 1 {)}^{2} }{(x + 1 {)}^{2} + (x - 1 {)}^{2} }$
$2)( \frac{(h + 1)(2h + 1) + {h}^{2} }{h(2h + 1)} )( \frac{h + 1 - (2 + h)}{h} ) = \frac{2 {h}^{2} + h + 2h + 1 + {h}^{2} }{h(2h + 1)} \times \frac{ - 1}{h} = \\ \frac{3 {h}^{2} + 3h + 1}{2 {h}^{2} + h } \times \frac{ - 1}{h} = \\ - \frac{3 {h}^{2} + 3h + 1}{h(2 {h}^{2} + h)}$
$3)( \frac{(m + 1 {)}^{2} - (m + 2 {)}^{2} }{(m + 2)(m + 1)} ) \div ( \frac{(m + 1) -(4 + 3m)}{m + 2} ) = \\ \frac{(m + 1 {)}^{2} - (m + 2 {)}^{2} }{(m + 2)(m + 1)} \times \frac{m + 2}{ - 3 - 2m} = \\ - \frac{( {m}^{2} + 2m + 1) - ( { {m}^{2} - 4m + 4})}{(m + 1)(3 + 2m)} = - \frac{6m - 3}{(m + 1)(3 + 2m)} = - \frac{3(2m - 1)}{(m + 1)(3 + 2m)}$