Task/26164769
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20 / (x² -7x+12) +10 / (x - 4) +1 ≥ 0 ;
20 / (x - 3)(x - 4) +10 / (x - 4) +1 ≥ 0 ;
(20 +10(x-3) + x² - 7x+12 ) / (x - 3)(x - 4) ≥ 0 ;
(x² +3x +2 ) / (x - 3)(x - 4) ≥ 0 ;
(x + 2) (x +1 ) / (x - 3)(x - 4) ≥ 0 ;
методом интервалов :
+ - + - +
////////////////// [ -2 ] ---------------[ -1] ///////////////////// (3)---------------(4) /////////////
Ответ : x∈ ( - ∞ ; -2 ] ∪ [ -1 ; 3) ∪ (4 ; + ∞) .