А)соs210° B)sin112°cos22°- sin22°cos112°

Question

А)соs210°
B)sin112°cos22°- sin22°cos112°

Answer 1

А) cos210° = cos(180° + 30°) = -cos(30°) = -√3/3
B) sin112°cos22° - sin22°cos112° = sin(112° - 22°) = sin(90°) = 1
Ответы: А) -√3/3; В)1