Помогите решить, пожалуйста срочно надо

Решите задачу:

$\left \{ {{x-y=1} \atop {xy=6}} \right. \left \{ {{x=1+y} \atop {xy=6}} \right. \\ (1+y)*y=6 \\ y=2 \\ y=-3 \\ x=3 \\ x=-2 \\ ( x_{1}, y_{1} ) =(3;2) \\ ( x_{2}, y_{2} )=(-2;-3) \\ \left \{ {{3-2=1} \atop {3*2=6}} \right. \\ \left \{ {{-2-(-3)=1} \atop {-2*(-3)=6}} \right. \\ \left \{ {{1=1} \atop {6=6}} \right. \\ \left \{ {{1=1} \atop {6=6}} \right. \\ ( x_{1}, y_{1} ) =(3;2) \\ ( x_{2}, y_{2} )=(-2;-3)$
$\left \{ {{x^2+2y^2=228} \atop {3x^2-2y^2=172}} \right. \\.................... \\ 4x^2=400 \\ x=-10 \\ x=10 \\ .................. \\ 10^2+2y^2=228 \\ 2y^2=128 \\ y^2=64 \\ y=-8 \\ y=8 \\ ( x_{1}, y_{1} ) =(-10;-8) \\ ( x_{2}, y_{2} )=(10;8)$