√(х+2)/(у-3)+√(у-3)/(х+2)=2
возведем обе части в квадрат:
[√(х+2)/(у-3)+√(у-3)/(х+2)]²=2²
(х+2)/(у-3)+2√(х+2)/(у-3)√(у-3)/(х+2)+(у-3)/(х+2)=4
(х+2)/(у-3)+2+(у-3)/(х+2)=4
[(x+2)²+(y-3)²]/[(х+2)*(у-3)]=2
(x+2)²+(y-3)²=2(х+2)*(у-3)
(x+2)²-2(х+2)*(у-3)+(y-3)²=0
((x+2)-(у-3))²=0
(x+2)-(у-3)=0
х+2-у+3=0
у=х+5
х+у=9
х+(х+5)=9
2х=4
х=2
у=7
№4
(1+√2)¹/³ * (3-2√2)¹/⁶=(1+√2)¹/³ * (2-2√2+1)¹/⁶=(1+√2)¹/³ * (√2-1)²*¹/⁶=
=(√2+1)¹/³ * (√2-1)¹/³=((√2+1)(√2-1))¹/³=(√2²-1²)¹/³=(2-1)¹/³=1¹/³=1