Решите алгебру №336 №340.Даю 35 баллов.Спс))) мне срочно надо

Решите задачу:

$1)\\ a^2+2ac+c^2=(a+c)^2\\ 2)\\ m^2-2mn+n^2=(m-n)^2\\ 3)\\ x^2-4xy+4y^2=(x-2y)^2\\ 4)\\ a^2+2ca+c^2=(a+c)^2\\ 5)\\ c^2+14c+49=(c+7)^2\\ 6)\\ k^2-6k+9=(k-3)^2$
$31^2=(30+1)^2=30^2+60+1 = 961\\ 51^2=(50+1)^2=50^2+100+1=2601\\ 39^2=(30+9)^2=30^2+18*30+9^2=1521\\ 103^2=(100+3)^2=100^2+6*100+3^2=10609\\ 99^2=(90+9)^2=90^2+18*90+9^2=9801\\ 999^2=(900+99)^2=900^2+2*99*900+99^2=998001\\ 1001^2=(1000+1)^2=1000^2+2000+1=1002001\\ 105^2=(100+5)^2=100^2+10*100+5^2=11025\\ 52^2=(50+2)^2=50^2+4*50+2^2=2704$