Sin A=5/13 Найти ctg если cos=12/13, tg=5/12
Tgα=sinα/cosα=(5/13)/(12/13)=5/12 0∠sinα,0∠cosα, α∈(0,90°) ctgα=1/tgα=1/(5/12)=12/5 ctgα=12/5