Log6(x-2)=log6 (2x+6) Срочно помогите!!!((
Log₆(x-2)=log₆(2x+6) ОДЗ: x>2. x∈(2;∞) x-2=2x+6 -x=8 x=-8. -8∉(2;∞) ответ: корней нет
![\left \{ {{x-2\ \textgreater \ 0} \atop {2x+6\ \textgreater \ 0}} \right. , \left \{ {{x\ \textgreater \ 2} \atop {x\ \textgreater \ -3}} \right. , =\ \textgreater \](https://tex.z-dn.net/?f=+%5Cleft+%5C%7B+%7B%7Bx-2%5C+%5Ctextgreater+%5C+0%7D+%5Catop+%7B2x%2B6%5C+%5Ctextgreater+%5C+0%7D%7D+%5Cright.+%2C+++++%5Cleft+%5C%7B+%7B%7Bx%5C+%5Ctextgreater+%5C+2%7D+%5Catop+%7Bx%5C+%5Ctextgreater+%5C+-3%7D%7D+%5Cright.+%2C+++%3D%5C+%5Ctextgreater+%5C+ "\left \{ {{x-2\ \textgreater \ 0} \atop {2x+6\ \textgreater \ 0}} \right. , \left \{ {{x\ \textgreater \ 2} \atop {x\ \textgreater \ -3}} \right. , =\ \textgreater \")