Номер 2:*********************

$\sqrt[3]{(72^2}) ^2 - \frac{36^ \frac{1}{6} }{2^ \frac{4}{3} } = \sqrt[3]{(2*4*9}) ^2 - \frac{\sqrt[6]{36}}{\sqrt[3]{2^4} } = \sqrt[3]{(2*2^2*3^2}) ^2 - \frac{\sqrt[6]{2^2*3^2}}{\sqrt[3]{2^4} } = 4*\sqrt[3]{3^4} - \frac{\sqrt[6]{2^2*3^2}}{\sqrt[3*2]{(2^(4*2)} } = 4*\sqrt[3]{3^4} - \sqrt[6]{ \frac{2^2*3^2}{2^8}} = 4*\sqrt[3]{3^4} - \sqrt[6]{2^{-6} *3^2} = 4*\sqrt[3]{ 9^{2}} - \frac{1}{2}*\sqrt[6]{9} = 4*\sqrt[3*2]{ 9^{2*2}} - \frac{1}{2}*\sqrt[6]{9} =$

$4*\sqrt[6]{ 9^{4}} - \frac{1}{2}*\sqrt[6]{9} = \sqrt[6]{9}(4*\sqrt[6]{ 9^{3}} - \frac{1}{2}) = \sqrt[6]{9}(4*\sqrt[6]{ 3^{2*3}} - \frac{1}{2}) = \sqrt[6]{9}(4*3 - \frac{1}{2}) = 11\frac{1}{2} *\sqrt[6]{9}$