Решите уравнения,пожалуйста

$(x + 6)(x - 1) - (x + 3)(x - 4) = 5x \\ {x}^{2} + 5x - 6 - ( {x}^{2} - x - 12) = 5x \\ - x - 18 = 0 \\ x = - 18$
$14 {x}^{2} - (2x - 3)(7x + 4) = 14 \\ 14 {x}^{2} - (14 {x}^{2} + 8x - 21x - 12) = 14 \\ 12x = 2 \\ x = \frac{1}{6}$
(8x+10)(3-x)=(11-2x)(4x+5)-5
24x-8x^2+30-10x=44x+55-8x^2-10x-5
14x+30=34x+50
-20x=20
X=-1
(X-6)(x-3)-(x+3)(x+9)=9
X^2+6x-3x-18-(x^2+9x+3x+27)=9
3x-18-12x-27=9
-9x=36
X=-4