А)log3 27 б)log5 1/25 в)log2 x=-3 г)log0,1 x=-2 д)logx 16=2

Question

А)log3 27
б)log5 1/25
в)log2 x=-3
г)log0,1 x=-2
д)logx 16=2

Answer 1

А)log_3 (27) => 3ˣ=27 => x=3
   log_3(27)=3
б)log_5 (1/25) => 5ˣ=1/25 => 5ˣ=1/5² => 5ˣ=5⁻² => x=-2
    log_5(1/25)=-2 
в)log_2(x)=-3 => x=2⁻³ => x=0.125
   log_2(0.125)=-3
г)log_0,1(x)=-2 => x=0.1⁻² => x=100
   log_0.1(100)=-2
д)log_x (16)=2 => x²=16 => x=√16 => x=4
    log_4(16)=2