Решите систему уравнений

$\left \{ {{ \frac{x}{y} + \frac{y}{x} = \frac{10}{3} } \atop {3x-2y=7}} \right.; \left \{ {{ \frac{3x^2+3y^2-10xy}{3xy} = 0} } \atop {3x-2y=7}} \right. ; \left \{ {{ 3x^2+3y^2-10xy = 0} } \atop {3x+7=2y}} \right. ; \left \{ {{ 12x^2+3*(2y)^2-20x*2y = 0} } \atop {3x+7=2y}} \right. ;\\ \left \{ {{ 12x^2+3(3x+7)^2-20x(3x+7) = 0} } \atop {3x+7=2y}} \right. ; \left \{ {{ 12x^2+3(9x^2+42x+49)-60x^2-140x = 0} } \atop {3x+7=2y}} \right. ;$

$\left \{ {{ 12x^2+27x^2+126x+147-60x^2-140x = 0} } \atop {3x+7=2y}} \right. ; \left \{ {{ -21x^2-14x+147 = 0} } \atop {3x+7=2y}} \right. ;\\ \left \{ {{ -7(3x^2+2x-21) = 0} } \atop {3x+7=2y}} \right. ; \left \{ {{ x= \frac{-2 \pm16}{6} } } \atop {y= \frac{3x+7}{2} }} \right. ; \left \{ {{ x= \frac{-1 \pm8}{3} } } \atop {y= \frac{3x+7}{2} }} \right. ; \left \{ {{ x=-3\ or\ \frac{7}{3} } \atop {y= \frac{3x+7}{2} }} \right. ;\\$

$\left \{ {{ x=-3} \atop {y= \frac{-9+7}{2} }} \right. \ or\ \left \{ {{ x=\frac{7}{3} } \atop {y= \frac{7+7}{2} }} \right. ;\\ \left \{ {{ x=-3} \atop {y= -1}} \right. \ or\ \left \{ {{ x=\frac{7}{3} } \atop {y=7 }} \right..$

Answer: $(-3;\ -1),\ ( \frac{7}{3};\ 7 )$