5-(а-3)=? 7+(12-2b)=? 64-(14+7х)=? 38+12р-8)=?

Question

5-(а-3)=? 7+(12-2b)=? 64-(14+7х)=? 38+12р-8)=?

Answer 1

5-a+3=0
-a=-8
a=8

7+12-2b=0
-2b=-19
b=9,5

64-14-7x=0
-7x=-50
x=50/7 примерно 7,14

38+12p-8=0
12p=-30
p=-2,5

Answer 2

5-(a-3)=5-а+3=8-а

7+(12-2b)=7+12-2b=10-2b

64-(14+7х)=64-14-7x=50-7x

38+(12р-8)=38+12p-8=30+12p
Вроде бы так