Система я забыла как реш

Решите задачу:

$\left \{ {{a-b=2} \atop {a^4-b^4=16}} \right. \\ \left \{ {{a-b=2} \atop {(a-b)(a+b)(a^2+b^2)=16}} \right. \\ \left \{ {{a-b=2} \atop {2(a+b)(a^2+b^2)=16}} \right. \\ \left \{ {{a=2+b} \atop {(a+b)(a^2+b^2)=8}} \right. \\ \left \{ {{a=2+b} \atop {(2+b+b)((2+b)^2+b^2)=8}} \right. \\ \left \{ {{a=2+b} \atop {2(1+b)(4+4b+2b^2)=8}} \right. \\ \left \{ {{a=2+b} \atop {2(1+b)(2+2b+b^2)=4}} \right. \\ \left \{ {{a=2+b} \atop {(1+b)(2+2b+b^2)=2}} \right.$
$\left \{ {{a=2+b} \atop {2+2b+2b+2b^2+b^2+b^3-2=0}} \right. \\ \left \{ {{a=2+b} \atop {b^3 + 3b^2+4b=0}} \right. \\ \left \{ {{a=2+b} \atop {b(b^2 + 3b+4)=0}} \right. \\ \left \{ {{a=2+b} \atop {b(b^2 + 3b+4)=0}} \right. \\ \left \{ {{a=2} \atop {b=0}} \right. \\ \\ OTBET: a=2, b=0$