5²x-6x+1=0; 4x²-36x+77=0

Question

5²x-6x+1=0; 4x²-36x+77=0

Answer 1

D=b2-4ac
D=36-20
x=-b+-кореньD/2a
x1=6-4/10=0.2
x2=6+4/10=1
x1=0.2
x2=1

D=bквадрат-4ac
D=1296-1232
D=64
x=-b+-кореньD
x1=36-8/8=3.5
x2=36+6/8=5.25
x1=3.5
x2=5.25