14x²-5x-1=0; 81y²-18y+1=0

Question

14x²-5x-1=0; 81y²-18y+1=0

Answer 1

14x^2-5x-1=0
D=b^2-4ac
D=81
x1.2=(-b±√D)/2a
x1=(5+9)/28=0,5
x2=(5-9)/28=-1/7

81y^2-18y+1=0
D=0
x=18/162=1/9