Нужно найти обратную матрицу

Решите задачу:

$\mathcal4=-4+9-6=-1\\A_{11}=(-1)^2* \left[\begin{array}{cc}4&0\\1&1\end{array}\right] =4\\A_{12}=(-1)^3* \left[\begin{array}{cc}3&0\\0&1\end{array}\right]=-3\\A_{13}=(-1)^4* \left[\begin{array}{cc}3&4\\0&1\end{array}\right]=3\\A_{21}=(-1)^3* \left[\begin{array}{cc}2&3\\1&1\end{array}\right]=1\\A_{22}=(-1)^4* \left[\begin{array}{cc}-1&3\\0&1\end{array}\right]=-1\\A_{23}=(-1)^5* \left[\begin{array}{cc}-1&2\\0&1\end{array}\right]=1\\A_{31}=(-1)^4* \left[\begin{array}{cc}2&3\\4&0\end{array}\right]=-12\\$
$A_{32}=(-1)^5* \left[\begin{array}{cc}-1&3\\3&0\end{array}\right]=9\\A_{33}=(-1)^6* \left[\begin{array}{cc}-1&2\\3&4\end{array}\right]=-10\\A^T= \left[\begin{array}{ccc}A_{11}&A_{21}&A_{31}\\A_{12}&A_{22}&A_{32}\\A_{13}&A_{23}&A_{33}\end{array}\right]=\left[\begin{array}{ccc}4&1&-12\\-3&-1&9\\3&1&-10\end{array}\right]\\A^{-1}=\frac{1}{\mathcal4}A^T=-1*\left[\begin{array}{ccc}4&1&-12\\-3&-1&9\\3&1&-10\end{array}\right]$