2х^3-х^2-2х+1=0 решите уравнение
2x³ - x² - 2x + 1 = 0
(2x³ - x²) - (2x - 1) = 0
x²(2x - 1) - (2x - 1) = 0
(x² - 1)(2x - 1) = 0
(x - 1)(x + 1)(2x - 1) = 0
x - 1 = 0 => x = 1
x + 1 = 0 => x = -1
2x - 1 = 0 => x = 1/2
Ответ: x = 1, x = 1/2, x = -1.