Помогите решить. Срочно!!! 40 балов

$\mathtt{-7\leq x\ \textless \ 4-x;~\left\{{{x\geq-7}\atop{2x\ \textless \ 4}}\right~\to~x\in[-7;2)}$

$\mathtt{-14\ \textless \ x+3\leq23-4x;~-17\ \textless \ x\leq20-4x~\to~x\in(-17;4]}$

$\mathtt{7-x\ \textless \ \frac{x-4}{2}\ \textless \ 9;~18-2x\ \textless \ x\ \textless \ 22~\to~x\in(6;22)}$

$\mathtt{x-6\leq\frac{x}{5}-2\leq3+2x;~-25-5x\leq4x\leq20~\to~x\in[-\frac{25}{9};5]}$

$\mathtt{|x|\leq5~\to~-5\leq x \leq5}$ и $\mathtt{|y|\ \textgreater \ 3~\to~\left[\begin{array}{ccc}\mathtt{y\ \textless \ -3}\\\mathtt{y\ \textgreater \ 3}\end{array}\right}$