(2+х)²= (4х-1)²= (2х+3у)²= (х²-5)²= (5х+2)²-20х=

Question

(2+х)²=
(4х-1)²=
(2х+3у)²=
(х²-5)²=
(5х+2)²-20х=

Answer 1

(2+x)²=4+4x+x²
(4x-1)²=16x²+8x-1
(2x+3y)²=4x²+6xy+9y²
(x²-5)²=x⁴+10x-25
(5x+2)²-20x=25x²+20x+4-20x=25x²+4