0,6(2х²+3) - 7(2-x²) = 2(3x²+1) - 1

Question

0,6(2х²+3) - 7(2-x²) = 2(3x²+1) - 1

Answer 1

0,6( 2х²+ 3 ) - 7( 2 - х²) = 2( 3х²+ 1 ) - 1
3/5 × ( 2х²+ 3 ) - 14 + 7х² = 6х²+ 2 - 1
6/5х²+ 9/5 - 14 + 7х² = 6х²+ 2 - 1
41/5х²- 6х² = 1 + 61/5
11/5х² = 66/5
х² = 6
х = + √6
х = √6
х = - √6
х = √6., х = - √6