Решите уравнение y-6]-[y-4]=3y 8y-3-[y+7]=4 9p-[11p-15]=289 3[2x+4]-[x-2]=35+[x-6]

Question

Решите уравнение y-6]-[y-4]=3y 8y-3-[y+7]=4 9p-[11p-15]=289 3[2x+4]-[x-2]=35+[x-6]

Answer 1

Y-6 - (y-4)=3y            8y-3-(y+7)=4           9p-(11p-15)=289
y-6-y+4-3y=0             8y-3-y-7-4=0          9p-11p+15-289=0
-3y=2                           7y=14                   -2p=274
y= - 2/3                         y=2                         p= - 137


3(2x+4)-(x-2)=35+(x-6)
6x+12-x+2= 35+x-6
5x+14-35-x+6=0
4x=15
x= 15/4  или 3 целые 3/4     или 3,75