Помогите решить : √(2-√3)=

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Помогите решить : √(2-√3)=


Алгебра (16 баллов) | 37 просмотров
Дан 1 ответ
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I hope this helps you


1<3<4 (3 nearest 4)<br>

√1<√3<√4<br>

1<√3<2<br>

√3=2,...


(2-√3)=2-2,...=-0,...


2-√3<0<br>

√2-√3=|2-√3|=√3-2

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1<√3<2 contradicts √3=2,... √3≈1.7

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and you √2-√3
and I have √(2-√3)

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yes I did a mistake report my answer please

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I do not know yet the answer
But! I solved such examples, but the Number A always was greater than B (a> b)
Example:
√ (11-4√7) = √ ((2-√7) ^ 2) =! 2-√7! = √7 -2
how to find A and B? Selection method. We take -4√7 divide by 2 (according to the formula (a-b) ^ 2 = a ^ 2 -2ab + b ^ 2), we get -2√7, where 2 = A, √7 = B (we check by substitution in formula, given to us the numbers are suitable).
Only here such a trick with my example does not pass ... ((