Помогите пожалуйста!!! 4 номер!!!! Срочно!!!!

$\sqrt{9-6 \sqrt{2} }= \sqrt{3(3-2 \sqrt{2}) } = \sqrt{3(2-2 \sqrt{2}+1) } =$ $\sqrt{3}* \sqrt{( \sqrt{2} ) ^{2}-2 \sqrt{2} +1 ^{2} }= \sqrt{3} * \sqrt{( \sqrt{2}+1) ^{2} }= \sqrt{3}*( \sqrt{2}+1)= \sqrt{6} +$ $\sqrt{3}$
2) $\sqrt{27+10 \sqrt{2} } = \sqrt{25+10 \sqrt{2}+2 } = \sqrt{5 ^{2} +10 \sqrt{2}+( \sqrt{2}) ^{2} } = \sqrt{(5+ \sqrt{2}) ^{2} }$ $=5+ \sqrt{2}$