Номер 14 сделайте пж

$\frac{6}{(x-3)(x-1)} + \frac{13-7x}{x-1} - \frac{3}{x-3}=0$
$\frac{6-13x+7 x^{2} +39-21x-3x+3}{(x-3)(x-1)} =0$
$\frac{7 x^{2} -37x+48}{(x-3)(x-1)} =0$
7x² - 37x + 48 = 0 x ≠ 3 , x ≠ 1
D = ( -37)² - 4 * 7 * 48 = 1369 - 1344 = 25
$X _{1} = \frac{37+ \sqrt{25} }{14}= \frac{37+5}{14}= \frac{42}{14}=3$
$X _{2}= \frac{37- \sqrt{25} }{14}= \frac{37-5}{14} = \frac{32}{14}= 2\frac{2}{7}$