Помогите, пожалуйста срочно !!!

1) y = 5x²² + 3
y' = (5x²²)' + 3' = 66x²¹
y'' = (66x²¹)' = 1386x²⁰
y''' = (1386x²⁰)' = 27 720 x¹⁹
2) y = ctg(π/3 - x)
y' = [ctg(π/3 - x)]' = - 1/Sin²(π/3 - x)* (π/3 - x)' = 1/Sin²(π/3 - x)
y'' = [1/Sin²(π/3 - x)]' = [Sin⁻²(π/3 - x)]' = - 2Sin⁻³(π/3 - x) * (π/3 - x)' =
= 2Sin⁻³(π/3 - x) = 2 / Sin³(π/3 - x)
3) $y' = ( \frac{2}{3x-4})' = \frac{2' * (3x-4) - 2 * (3x-4)'}{(3x-4) ^{2} } = - \frac{6}{(3x-4) ^{2} }$
$y'' = [ -6(3x-4) ^{-2}]' = 12(3x-4) ^{-3} * (3x-4)' = 36(3x-4) ^{-3} =$ $\frac{36}{(3x-4) ^{3} }$