Решите неравенство Log(5x-1)2 меньше равен 0 (5x-1) основание

$log_{(5x-1)}2 \leq 0\\\\ 1) 0 \ \textless \ 5x - 1 \ \textless \ 1\\ (5x-1)^0 \leq 2\\ 1 \leq 2-verno.dlya.lubogo.x\\ 0 \ \textless \ 5x-1\ \textless \ 1\\ 1\ \textless \ 5x\ \textless \ 2\\ 0,2\ \textless \ x\ \textless \ 0,4\\\\ 2)5x-1\ \textgreater \ 1\\ (5x-1)^0 \geq 2\\ 1 \geq 2-ne.verno\\$

Ответ: x∈(0,2; 0,4)