1) 3x^2+4x-1=0 2) -49x^2+21x-2=04

Question

1) 3x^2+4x-1=0 2) -49x^2+21x-2=04

Answer 1

1) D= 4² - 4*3*(-1)=16+12=28
x1 = (-4-√28)/(2*3) = (-2-√7) / 3 ≈1.549
x2 =(-4-√28)/(2*3) = (-2-√7) / 3 ≈1.549

2) D = 21² - 4(-49)(-2) = 441-392=49
x1=(-21-7)/ 2*(-49) = -28/(-98) = 2/7
x2=(-21+7)/ 2*(-49) = -14/(-98) = 1/7