Решите задачу:
Пусть \frac{ \sqrt{x} }{2} " alt=" \frac{ {a}^{2} - 3a }{2a - 6} = \frac{a(a - 3)}{2(a - 3)} = \frac{a}{2} = > \frac{ \sqrt{x} }{2} " align="absmiddle" class="latex-formula">
\frac{ \sqrt{x} }{2} " alt=" \frac{ {a}^{2} - 3a }{2a - 6} = \frac{a(a - 3)}{2(a - 3)} = \frac{a}{2} = > \frac{ \sqrt{x} }{2} " align="absmiddle" class="latex-formula">