Система y=x^2-4 2x+y=-1

Решите задачу:

$\left \{ {{y=x^2-4} \atop {2x+y=-1}} \right. \\ \left \{ {{y=x^2-4} \atop {2x+x^2-4+1=0}} \right. \\ \left \{ {{y=x^2-4} \atop {x^2+2x-3=0}} \right. \\ \\ \left \{ {{y_1=x_1^2-4} \atop {x_1=1}} \right. \\ \left \{ {{y_2=x_2^2-4} \atop {x_2=-3}} \right. \\ \\ \left \{ {{y_1=-3} \atop {x_1=1}} \right. \\ \left \{ {{y_2=5} \atop {x_2=-3}} \right. \\ \\ OTBET:(1; -3), (-3;5)$