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Решите задачу:

$\displaystyle 3 \frac{1}{4}-( \frac{6: \frac{3}{5} -1 \frac{1}{6}* \frac{6}{7}}{4 \frac{1}{5}* \frac{10}{11}+5 \frac{2}{11}}- \frac{ (\frac{3}{20}+ \frac{1}{2}- \frac{1}{15})* \frac{12}{49}}{ \frac{1}{5}+ \frac{1}{7}})*2 \frac{1}{3}=\\\\\\=3 \frac{1}{4} -(\frac{10-1}{\frac{42}{11}+\frac{57}{11}}-\frac{\frac{35}{60}*\frac{12}{49}}{\frac{12}{35}})*2 \frac{1}{3}=3\frac{1}{4} -(1- \frac{5}{12}})* \frac{7}{3}=\\\\\\=\frac{13}{4} - \frac{49}{36}=\frac{117-49}{36}=\frac{68}{36}=1\frac{8}{9}$