5к²-7 к+2<0 решите неравенство

Я возьму к как х
5 $x^{2}$ -7x+2<0<br>5 $x^{2}$ -2x-5x+2<0<br>x(5x-2)-(5x-2)<0<br>(x-1)(5x-2)<0<br>рассматриваем два случая:
\frac{2}{5} }} \right. " alt="1) \left \{ {{x-1\ \textless \ 0} \atop {5x-2\ \textgreater \ 0}} \right. = \left \{ {{x<1} \atop {x >\frac{2}{5} }} \right. " align="absmiddle" class="latex-formula">
$2) \left \{ {{x-1\ \textgreater \ 0} \atop {5x-2\ \textless \ 0}} \right. = \left \{ {{x\ \textgreater \ 1} \atop {x\ \textless \ \frac{2}{5} }} \right.$
1) x∈( $\frac{2}{5}$ ;1)
2) x∉∅