А) √175 = √25*7 = 5√7; б) \frac{5}{6} \sqrt{36*5} = \frac{5}{6} 6 \sqrt{5}
= 5 \sqrt{5} ;в) \sqrt{ \frac{7 (a^{5}) ^{2} }{36} } = \frac{ a^{5} \sqrt{7} }{6} ;
2. = \sqrt{96} ; \sqrt{ \frac{1}{36}*108a } = \sqrt{3a} ;
\frac{3 \sqrt{17} }{4} \ \textless \ 9 \sqrt{ \frac{1}{8} } ;
= \frac{ \sqrt{abc}+ b\sqrt{c}+b \sqrt{a}- \sqrt{abc} }{b \sqrt{ab} } = \frac{ \sqrt{c}+ \sqrt{a} }{ \sqrt{ac} }