Решите систему x^3-y^3=6 x-y=2

Question

Решите систему
x^3-y^3=6
x-y=2

Answer 1

(x-y)(x^2+xy+y^2)=6
x-y=2
x^2+xy+y^2=3
x=2+y
y^2+4y+4+y^2+2y+y^2=3
3y^2+6y+1=0
D=24
y1,2=(-5+-sqrt(24))/6
x1=2+(-5+sqrt(24))/6
x2=2+(-5-sqrt*24))/6