Решите алгебру пожалуйста

▪1.
$a) \: \: 6y \times 3 {a}^{2} = 18 {a}^{2} y$
б)
$8 {a}^{2} \times ( - \frac{1}{4} y) = - \frac{8 {a}^{2} }{4} y = - 2 {a}^{2} y$
в)
${x}^{2} {y}^{2} \times 3.2 {y}^{3} {x}^{6} = 3.2 {x}^{8} {y}^{5}$
г)
$(7a) ^{2} = 49 {a}^{2}$
д)
${( \frac{1}{2} {a}^{2} {b}^{6} )}^{3} = \frac{1}{8} {a}^{6} {b}^{18}$
е)
$(10 {x}^{4} {y}^{4} ) ^{2} = 100 {x}^{8} {y}^{8}$
ж)
$- {( - 3 {a}^{6} {b}^{2} )}^{3} = - ( - 27 {a}^{18} {b}^{6} ) = 27 {a}^{18} {b}^{6} \:$
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▪2.
а)
$- 8 {x}^{2} y \times (2x {y}^{2} ) = - 16 {x}^{3 } {y}^{3} \:$
б)
$- 2{p}^{4} \times ( - 6 {p}^{2} ) = 12 {p}^{6}$
в)
$2 {x}^{2} \times 3 {x}^{3} = 6 {x}^{5}$
г)
${( - 2x {y}^{2}) }^{3} = - 8 {x}^{3} {y}^{6}$
д)
$4 {a}^{5} b \times a = 4 {a}^{6} b$