Решите примеры и поясните как решать.

1) $\frac{2 ^{9}*3 ^{9} }{6 ^{7} }= \frac{2 ^{9}*3 ^{9} }{(2*3) ^{7} } = \frac{2 ^{9}*3 ^{9} }{2 ^{7} *3 ^{7} }=2 ^{9-7}*3 ^{9-7}=2 ^{2}*3 ^{2}=4*9 = 36$
2) $\frac{18 ^{7} }{2 ^{6}*9 ^{6} } = \frac{(2*9) ^{7} }{2 ^{6} *9 ^{6} } = \frac{2 ^{7}*9 ^{7} }{2 ^{6}*9 ^{6} } =2 ^{7-6}*9 ^{7-6}=2*9 = 18$
3) $\frac{7 ^{9}*5 ^{8} }{35 ^{8} }= \frac{7 ^{9} *5 ^{8} }{(7*5) ^{8} } = \frac{7 ^{9}*5 ^{8} }{7 ^{8} *5 ^{8} } =7 ^{9-8}*5 ^{8-8}=7 *5 ^{0}= 7*1= 7$
4) $\frac{2 ^{9}*5 ^{14} }{50 ^{7} }= \frac{2 ^{9}*5 ^{14} }{(2*5 ^{2}) ^{7} }= \frac{2 ^{9} *5 ^{14} }{2 ^{7} *5 ^{14} }=2 ^{9-7} = 2 ^{2} =4$