Sin(2x-π/4)=√3/2. Помогите.

$sin(2x- \dfrac{\pi}{4})= \dfrac{\sqrt3}{2}$
$\left[\begin{array}{I} 2x- \dfrac{\pi}{4}= \dfrac{\pi}{3} + 2\pi k \\ 2x- \dfrac{ \pi }{4}= \pi - \dfrac{ \pi }{3}+2 \pi k \end{array}}$
$\left[\begin{array}{I} 2x= \dfrac{7 \pi}{12}+2 \pi k \\ 2x= \dfrac{11 \pi }{24}+2 \pi k \end{array}}$
$\left[\begin{array}{I} x= \dfrac{7 \pi }{24}+ \pi k \\ x= \dfrac{11 \pi}{24}+ \pi k \end{array}};\ k \in Z$ - это ответ