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Решите задачу:

$3)( - \frac{3}{4} - \frac{1}{6} ) \div ( - 1 \frac{3}{8} )$
$- \frac{3}{4} - \frac{1}{6} = - \frac{3 \times 3}{3 \times 4} - \frac{2 \times 1}{2 \times 6} = - \frac{9}{12} - \frac{2}{12} = \frac{ - 9 - 2}{12} = - \frac{11}{12}$
$- \frac{11}{12} \div ( - 1 \frac{3}{8} ) = - \frac{11}{12} + ( - \frac{1 \times 8 + 3}{8} ) = - \frac{11}{12} \div ( - \frac{11}{8} ) = - \frac{11}{12} \times ( - \frac{8}{11} ) = \frac{11 \times 8}{12 \times 11} = \frac{88}{132} = \frac{2}{3}$

$4)( \frac{1}{4} - \frac{5}{18} ) \times 36$
$\frac{1}{4} - \frac{5}{18} = \frac{9 \times 1}{9 \times 4} - \frac{2 \times 5}{2 \times 18} = \frac{9}{36} - \frac{10}{36} = \frac{9 - 10}{36} = - \frac{1}{36}$
$- \frac{1}{36} \times 36 = - \frac{1}{36} \times \frac{36}{1} = - \frac{1 \times 36}{36 \times 1} = - \frac{36}{36} = - 1$