Cosx/4=√3/2
x/4=-π/6+2πk,k∈z Y x/4=π/6+2πk,k∈z
x=-2π/3+8πk,k∈z U x=2π/3+8πk,k∈z
cosx/3=-1/2
x/3=-2π/3+2πk,k∈z U x/3=2π/3+2πk,k∈z
x=-2π+6πk,k∈z U x=2π+6πk,k∈z
sin2x = - √3/2
2x=-π/3+2πk,k∈z U 2x=-2π/3+2πk,k∈z
x=-π/6+πk,k∈z U x=-π/3+πk,k∈z
tgx = √3/2
x=arctg√3/2+πk,k∈z
tg(x-п/6) = 1/√3
x-π/6=π/6+πk,k∈z
x=π/3+πk,k∈z
tgx = - √3/3
x=-π/6+πk,k∈z
cos 5x = 3>1 нет решения
sin x/2 = -2<-1 </span>нет решения
tg 3x ( √2 - sin x) = 0
[tg3x=0⇒3x=πk,k∈z⇒x=πk/3,k∈z
[sinx=√2>1 нет решения
Ответ x=πk/3,k∈z