48t2−(12t−4)⋅(4t+1)=−2

Question

48t2−(12t−4)⋅(4t+1)=−2

Answer 1

48t²−(12t−4)⋅(4t+1)=−2
48t²-48t²-12t+16t+4=-2
-12t+16t=-2-4
4t=-6
t=-6:4
t=-1.5

Comments

реши

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только ответ

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12t^2−12t^2-4t+9t+3=-2;9t-4t=-2-3;5t=-5;t=-5:5;t=-1

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всё ок

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(13y+1)⋅(2y−4)=(26y−5)(y+1)

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помоги

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26y^2-52y+2y-4=26y^2+26y-5y-5;26y^2-52y+2y-26y^2-26y+5y=4-5=-71y=-1; у=-1:71;у=-1/71

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0,2d(2d2−3)(3d2+10)

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помоги

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=(0.4d^3-0.6d)(3d^2+10)=1.2d^5+4d^3-1.8d^3+6d=1.2d^5+3.2d^3+6d