Решите пожалуйста №5,6 умоляю!!!

5a) $\frac{3x-7}{8} *24- \frac{x-3}{6} *24=1*24$
3(3x - 7) - 4(x - 3) = 24
9x - 21 - 4x + 12 = 24
5x - 9 = 24
5x = 15
x = 3
5б) (3x + 4)(4x - 3) - 5 = (2x + 5)(6x - 7)
12x² - 9x + 16x - 12 - 5 = 12x² - 14x + 30x - 35
12x² + 7x - 12x² - 16x = - 35 + 12 + 5
- 9x = - 18
x = 2
6) 24ab + 32a - 3b - 4 = (24ab + 32a) - (3b + 4) = 8a(3b + 4) - (3b + 4) =
= (3b - 4)(8a - 1)
$[3*(- 1 \frac{2}{3})-4](8*0,3-1) =(-3* \frac{5}{3} -4)(2,4 -1)=(-5-4)*1,4=$ -9*1,4=-12,6