выразим у через х
у = 7-х
подставим выражение в первое уравнение
x² + (7-x)² = 65
x² + 49 - 14x +x² = 65
2x² - 14x -16 = 0
D=b² - 4ac = 14² - 4*2*(-16) = 196 + 128 = 324

=
![\frac{-b + [tex] \sqrt{D} \frac{-b + [tex] \sqrt{D}](https://tex.z-dn.net/?f=+%5Cfrac%7B-b+%2B+%5Btex%5D+%5Csqrt%7BD%7D+)
}{2a} [/tex] =
=

= 8

=
![\frac{-b - [tex] \sqrt{D} \frac{-b - [tex] \sqrt{D}](https://tex.z-dn.net/?f=+%5Cfrac%7B-b+-+%5Btex%5D+%5Csqrt%7BD%7D+)
}{2a} [/tex] =
=

= -1

= 7 - 8 = -1

= 7 - (-1) = 8
Ответ: (8; -1), (-1;8)