(4-3x)(x^2-64)(|7x+2|-10)(|x|+100)=0 Решите плиз...

Question

(4-3x)(x^2-64)(|7x+2|-10)(|x|+100)=0

Решите плиз...

Answer 1

(4-3x)(x^2-64)(|7x+2|-10)(|x|+100)=0

 

1) 4-3x=0 => 3x=4 => x=4/3

2) x^2-64=0 => x^2=64 => x=±8

3) |7x+2|-10=0 => |7x+2|=10

     A) 7x+2>0 => 7x>-2 => x>-2/7

           7x+2=10 => 7x=10-2=> 7x=8 =>x=8/7

B)     7x+2<0 => 7x<-2 => x=-2/7

7x+2=-10 => 7x=-12 => x=-12/7

4) |x|+100=0 => |x|=-100 – нет решений

 

ОТВЕТ: x=4/3; x=±8; x=8/7; x=-12/7