Вроде так:
1) (x * 2 - 1)(x + 2) > 0
(2x - 1)(x + 2) > 0
{2x - 1 > 0; x + 2 > 0
{2x - 1 < 0; x + 2 < 0
{x > 1/2; x > -2
{x < 1/2; x < -2
x ∈ (-∞; -2) ∪ (1/2; +∞)
2) 2 - (x / (3+x)) ≥ 0
(2(3 + x) - x) / (3 + x) ≥ 0
(6 + 2x - x) / (3 + x) ≥ 0
(6 + x) / (3 + x) ≥ 0
{6 + x ≥ 0; 3 + x ≥ 0
{6 + x ≤ 0; 3 + x ≤ 0
{x ≥ -6; x > -3
{x ≤ -6; x < -3
x ∈ (-∞; -6] ∪ (-3; +∞)