Найдите значение выражений 24y^3 - 3(8y^2-1)(y+6) при y= -2/3 40 m^3 - (5m^2 + m - 2...

1) 24y³ - 3(8y² - 1)(y + 6) = 24y³ - 3(8y³ + 48y² - y - 6) = 24y³ - 24y³ - 144y² +
+ 3y + 18 = - 144y² + 3y + 18
$- 144*(- \frac{2}{3} ) ^{2}+3*(- \frac{2}{3}) +18=- 144* \frac{4}{9}-2 +18=-64+16=- 48$
2) 40m³ - (5m² + m - 2)(8m + 3) = 40m³ - 40m³ - 15m² - 8m²- 3m + 16m + 6 =
= - 23m² + 13m + 6 $- 23*( \frac{7}{10} ) ^{2} +13* \frac{7}{10} +6= - 23* \frac{49}{100} + \frac{91}{10}+6=- 11,27+9,1 + 6=$ $3,83$