Помогите решить задания ниже,пожалуйста!

Задание 17)
$1 + {x}^{2} - 2x = {(1 - x)}^{2}$
$9 {x}^{2} - xy + \frac{1}{36} {y}^{2} = {(3x - \frac{1}{6} y)}^{2}$
$64 - 16a + {a}^{2} = {(8 - a)}^{2}$
${m}^{2} + 2mn + {n}^{2} = {(m + n)}^{2}$

Задание 18)
$(2x + 1)(2x - 1) = 4 {x}^{2} - 1$
$(4c + 9d)(9d - 4c) = 81 {d}^{2} - 16 {c}^{2}$
$(8b + 5a)(8b - 5a) = 64 {b}^{2} - 25 {a}^{2}$
$(c + d)(c - d) = {c}^{2} - {d}^{2}$

Задание 19)
$125 {a}^{3} - 64 {b}^{3} = (5a - 4b)(25 {a}^{2} + 20ab + 16 {b}^{2} )$
${c}^{3} - {d}^{3} =(c - d) ( {c}^{2} + cd + {d}^{2} )$
$27 - {y}^{3} = (3 - y)(9 + 3y + {y}^{2} )$
$(1 - c )(1 + c + {c}^{2} )$