1. (11\15+2 5\9)*3 2. 4*1\3-(1\3)два в квадрате *39

Question

1. (11\15+2 5\9)*3

2. 4*1\3-(1\3)два в квадрате *39

Answer 1

1) = (2 (33+15)/45)*3=3 3/45*3=138/45*3=9 3/15=9 1/15