Тригонометрия!!!! Очень надо sin^2 (x-Пи/4)=0,75 Решите уравнение плииз
Sin²(x-π/4)=0,75 Sin(x-π/4) = +-√3/2 а)Sin(x-π/4) = √3/2 x -π/4= (-1)^n arcSin√3/2 + nπ, n ∈Z x = π/4 +(-1)^nπ/3 + πn , n ∈Z б) Sin(x-π/4) = -√3/2 x -π/4= (-1)^k arcSin(-√3/2 )+ kπ, k ∈Z x = π/4 +(-1)^(k+1)π/3 + πk , k∈Z