Система y+4x=6 x^2+3xy-y^2=3

Решите задачу:

$\left \{ {{y+4x=6} \atop {x^2+3xy-y^2=3}} \right. \Rightarrow \left \{ {{y=6-4x} \atop {x^2+3x(6-4x)-(6-4x)^2=3}} \right. \Rightarrow \\ \Rightarrow\left \{ {{y=6-4x} \atop {x^2+18x-12x^2-36+48x-16x^2-3=0}} \right. \Rightarrow \\ \Rightarrow \left \{ {{y=6-4x} \atop {27x^2-66x+39=0}} \right. \Rightarrow \left \{ {{y=6-4x} \atop {9x^2-22x+13=0}} \right. \Rightarrow \\ \Rightarrow \left \{ {{y=6-4x} \atop {x= \frac{22б 4 }{18} }} \right.$
$\left \{ {{y=6-4x} \atop {x= \frac{11б2}{9} }} \right. \Rightarrow \\ \left \{ {{x= \frac{13 }{9} } \atop {y=6- \frac{52 }{9} =\frac{2 }{9} }} \right. or \left \{ {{x= 1 } \atop {y=6- 4= 2 } \right.$